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-6p^2-5p+1.5=0
a = -6; b = -5; c = +1.5;
Δ = b2-4ac
Δ = -52-4·(-6)·1.5
Δ = 61
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-5)-\sqrt{61}}{2*-6}=\frac{5-\sqrt{61}}{-12} $$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-5)+\sqrt{61}}{2*-6}=\frac{5+\sqrt{61}}{-12} $
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